8q^2-3q-2=0

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Solution for 8q^2-3q-2=0 equation: 



8q^2-3q-2=0

a = 8; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·8·(-2)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{73}}{2*8}=\frac{3-\sqrt{73}}{16}
$


$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{73}}{2*8}=\frac{3+\sqrt{73}}{16}
$

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